cat: how can I skip the first n lines?

You can use the `tail` command in Unix/Linux systems to skip the first `n` lines of a file or a stream. If you want to skip the first `n` lines, the general command format will be: ``` tail -n + ``` `` here is the number of the line from where you want to start output. So to skip first 10 lines of a file named "file.txt", you would do: ``` tail -n +11 file.txt ``` `tail -n +11` means start output from line number 11 (skips the first 10 lines). Keep in mind that the `-n` option specifies the number of lines, and the '+' means 'start from'. This command will print the remainder of the file to the standard output (usually your terminal), it won't change the original file. If you need to capture this output, you can redirect it into another file: ``` tail -n +11 file.txt > newfile.txt ``` In this case, the "newfile.txt" will contain the contents from line 11 onwards from "file.txt". Remember, all these commands works on the premise that you have access to a Unix/Linux terminal. If you are trying to do this programmatically within a certain language, the methods will vary.

You can skip the first n lines of a file in Unix-like systems using the `tail` command combined with the `-n` option. Suppose you want to skip the first 5 lines, you'd do: ```bash tail -n +6 filename ``` The `+6` means start output at the 6th line of the file (hence skipping the first 5). Remember, `tail`, by default, prints the last 10 lines, so using `-n +6` tells it to start at line 6, thus showing everything from line 6 onwards. Here `filename` is the name of your text file. Replace it with your actual file name. This command displays all lines starting from the 6th line. To save the result use shell redirection: ```bash tail -n +6 filename > newfile ``` Here `newfile` is the name of the new file where you will save the result. Again, this kind of command is common in Unix or Unix-like system. For a different OS, you might need a different command or tool.